maximum: Number

Comments 9

1. Hi,
   What if the difference between my minimum and maximum value is just .01? My graph shows no significant changes. I want to automatically change the points to like .01 to see the significant change in my graph. help please.

   • edit: I already fixed this by using the property includeZero=”false”; thanks!

2. what if I only want to put tickMarks on a specified minimum and maximum but i still want to show the rest of the graph beyond the maximum and below minimum?

   • vianece,

     Sorry this is not possible.

3. Is it possible to calculate y-axis on a log-scale?

   • [Update]
     We have just released v1.9.0 Beta-1 with logarithmic axis. Please refer to the release blog for more information.

     Right now canvasjs api doesn’t have logarithmic axisY. But you can workaround this as shown in this jsfiddle.

   • [Update]

     We have just released v1.9.0 Beta-1 with logarithmic axis. Please refer to the release blog for more information.

4. Hello, I am trying to display two charts side-by-side. mainChart displays the entire dataset with auto-scaled Y-axis. subChart shows a subset of the data but I would like its Y-axis to have the same scaling that was calculated for the mainChart, like this:

   var mainChart = new CanvasJS.Chart(“container”,
   {
   axisY:{
   // maximum not set (automatic scaling)
   }, },
   });
   mainChart.render();

   var subChart = new CanvasJS.Chart(“container”,
   {…
   },
   });
   subChart.options.axisY.maximum = mainChart.options.axisY.maximum,
   subChart.render();

   But mainChart.options.axisY.maximum is not defined. Is there another way to retrieve the axis range that was calculated?

   • Phil,
     It is not possible to set the axis maximum from one chart to another chart directly. As a workaround you can calculate the maximum of Y-axis data and then assign the axisY maximum for both the charts using
     chart1.options.axisY.maximum = chart2.options.axisY.maximum = maxValue(chart1.options.data[0].dataPoints);

     Here is an example that will help you.