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Issues retrievng data from MySql

Viewing 13 posts - 16 through 28 (of 28 total)
1 2
  • November 5, 2014 at 7:49 pm #7478

    andres.chandia

    Sorry, I’m lost now, I don’t know what you mean I should do, you mean PHP echo statements…?

    November 6, 2014 at 12:29 pm #7484

    andres.chandia

    Could you please give me an exemple of what you mean to see if I can folow you… thanks…

    November 9, 2014 at 8:07 am #7488

    andres.chandia

    I’m really sorry my friend, I’m going round in circles, I have been searching and searching but I can not know what you mean with your answer, so I don’t know where to head me to, would you have a little mercy on me and give me a hand, I would thank you for ever.

    November 11, 2014 at 5:44 pm #7490

    Sunil Urs

    Andres,

    Yes, you need to use php echo statements for the same. Currently we are occupied with some other tasks. If you can give us a day or two we can create a simple example for you.

    —
    Sunil Urs

    November 12, 2014 at 2:15 pm #7497

    andres.chandia

    Of course my friend, take your time, I’ll be waiting for your help….

    November 13, 2014 at 6:26 pm #7499

    Anjali

    Andres,

    Here is a modified version of our previous example where we generate JSON data using echo statements.

    Below is the sample code

    1. PHP Service to return JSON Data using echo statements:

    <?php

	$conn = new mysqli("127.0.0.1","user","password", "chartDb");

	// Check connection
	if ($conn->connect_error) {
		die("Connection failed: " . $conn->connect_error);
	} else
	{
		$data_points = array();
		
		$result = mysqli_query($conn, "SELECT * FROM pie_chart");

		while($row = mysqli_fetch_array($result))
		{        
			$point = array("label" => $row['Support'] , "y" => $row['yValues']);
			array_push($data_points, $point);        
		}

		//echo json_encode($data_points, JSON_NUMERIC_CHECK);

		// JSON data using echo statements
		
		$length = sizeof($data_points);

		echo "[";
		for ( $i = 0; $i <= $length-1; $i++) { 
			echo "{ \"label\": \"" , $data_points[$i]['label'],"\", \"y\": " , $data_points[$i]['y'], "}";
			if( $i < $length-1)
				echo ",";
		}
		echo "]";	
	}
?>

    2. HTML Page to Fetch Data and render Chart

    <html>
<head>
<script src="jquery-1.11.1.min.js"></script>
<script src="canvasjs.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
	var dataPoints = [];
        $.getJSON("data.php", function (result) {
            var chart = new CanvasJS.Chart("chartContainer", {
                data: [
                    {
                        type: "pie",
                        dataPoints: result
                    }
                ]
            });
            chart.render();
        });
    });
</script>
</head>
<body>
       <div id="chartContainer" style="width:500px; height: 300px"></div>
</body>
</html>

    __
    Anjali

    • This reply was modified 10 years, 1 month ago by Anjali.
    November 18, 2014 at 12:38 am #7510

    andres.chandia

    Sorry for this but I’ve been testing the code and no success, no graphic comes out, here are my files, I think I’ve adapted them well, but maybe I’m doing something wrong…

    tipus_recursos.php

    <?php
$conn = new mysqli("localhost","dbuser","dbpassword","database");

        // Check connection
        if ($conn->connect_error) {
                die("Connection failed: " . $conn->connect_error);
        } else
        {
                $data_points = array();
                $result = mysqli_query($conn, "SELECT <code>Tipus_1</code> AS 'Tipus', COUNT(*) AS 'Recursos' FROM <code>values</code>");

                while($row = mysqli_fetch_array($result))
                {
                        $point = array("label" => $row['Recursos'] , "y" => $row['Tipus']);
                        array_push($data_points, $point);
                }

                //echo json_encode($data_points, JSON_NUMERIC_CHECK);
                // JSON data using echo statements
                $length = sizeof($data_points);

                echo "[";
                for ( $i = 0; $i <= $length-1; $i++) { 
                        echo "{ \"label\": \"" , $data_points[$i]['label'],"\", \"y\": " , $data_points[$i]['y'], "}";
                        if( $i < $length-1)
                                echo ",";
                }
                echo "]";
        }

?>

    tipus_recursos.js

    $(document).ready(function () {
        var dataPoints = [];
        $.getJSON("tipus_recursos.php", function (result) {
            var chart = new CanvasJS.Chart("chartContainer2", {
                data: [
                    {
                        type: "pie",
                        dataPoints: result
                        indexLabel: "#percent"
                    }
                ]
            });
            chart.render();
        });
    });

    graf_tipus_recursos.php

    <head>
       <script src="jquery.js"></script>
        <script src="canvasjs.js"></script>
        <script src="tipus_recursos.js"></script>
</head>
<body>
<h2>Gràfic per tipus de recursos</h2>
<div id="chartContainer2" style="width: 1200px; height: 700px;" ></div>
</body>
    November 18, 2014 at 4:41 pm #7511

    andres.chandia

    Sorry again, I could do it, I did a merge between original file and the one proposed by you, and I could get it, but I have the encoding issues anyway you can check it here: http://parles.upf.edu/llocs/adljc/grafics/graf_tipus_recursos.php, this is the resulting file:

    tipus_recursos.php

    <?php
header('Content-Type: application/json');
$con = mysqli_connect("localhost","dbuser","dbpassword","database");
// Check connection
if (mysqli_connect_errno($con))
{
    echo "Failed to connect to DataBase: " . mysqli_connect_error();
}else
{
    $data_points = array();
    $result = mysqli_query($con, "SELECT <code>Tipus_1</code> AS 'Tipus', COUNT(*) AS 'Recursos' FROM <code>values</code> GROUP BY <code>Tipus_1</code> DESC");
    while($row = mysqli_fetch_array($result))
    {
        $point = array("label" => $row['Tipus'] , "y" => $row['Recursos']);
        array_push($data_points, $point);
    }
//    echo json_encode($data_points, JSON_NUMERIC_CHECK);
        $length = sizeof($data_points);
                echo "[";
                for ( $i = 0; $i <= $length-1; $i++) { 
                        echo "{ \"label\": \"" , $data_points[$i]['label'],"\", \"y\": " , $data_points[$i]['y'], "}";
                        if( $i < $length-1)
                                echo ",";
                }
                echo "]";
}
mysqli_close($con);
?>
    November 18, 2014 at 4:47 pm #7513

    andres.chandia

    I have tried:
    mysql_set_charset('utf8',$con);
    and
    header('Content-Type: text/html; charset=utf-8');
    but no success…

    November 20, 2014 at 6:14 pm #7535

    andres.chandia

    So, any ideas about the encoding stuff?

    November 27, 2014 at 4:08 pm #7550

    andres.chandia

    It seems there is no possible solution for this, isn’t it?

    December 1, 2014 at 7:03 pm #7558

    Anjali

    Andres,

    I just got it working by using $conn->set_charset(‘utf8’); before fetching the data. Please try with the below code.

    $con = mysqli_connect("localhost","dbuser","dbpassword","database");
$conn->set_charset('utf8');

    __
    Anjali

    December 2, 2014 at 10:25 pm #7569

    andres.chandia

    Yes, thanks a lot, that did it….

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